Vesiniku rõhk

Ülesanne. Vesiniku molekulide ruutkeskmine kiirus on 4000 space m over s ja molekulide kontsentratsioon on 10 to the power of 25 space m to the power of negative 3 end exponent. Arvuta vesiniku rõhk.


Lahendus. Paneme kirja andmed.

Antud:
square root of stack v with rightwards harpoon with barb upwards on top squared with bar on top end root equals 4000 space m over s
n equals 10 to the power of 25 space m to the power of negative 3 end exponent
m subscript v e sin i k end subscript equals 2 times 1 comma 66 times 10 to the power of negative 27 end exponent space k g
minus negative negative negative negative negative negative negative negative negative negative negative negative
p equals ?

Ülesande andmetesse oleme lisanud vesiniku molekulmassi, mis on kaks aatommassiühikut (vesiniku molekul koosneb kahest aatomist). Edasi asendame suurused ideaalse gaasi rõhu valemisse ning arvutame:

p equals 1 third n m subscript v e sin i k end subscript stack v squared with bar on top equals 1 third times 10 to the power of 25 space m to the power of negative 3 end exponent times 2 times 1 comma 66 times 10 to the power of negative 27 end exponent space k g times 16 times 10 to the power of 6 space m squared over s squared equals 1 comma 8 times 10 to the power of 5 space P a.

VASTUS: vesiniku rõhk on 1 comma 8 times 10 to the power of 5 space P a.